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ECEN 326 Lab6 Report

ECEN 326

Lab6 Report

Calculations:

NPN simple circuit:

Given RE1 = RE2 = 100 Ohms, Io = 1 mA

Find RC:

1e-3 = (5 - 0.7) / ( RC + 100) * 100 /1 00

RC = 4200 Ohms

Find Vo,min:

Vo,min = 0.2 + 1e-3 * 100 = 0.3V

Find Ro:

gm2 = gm1 = 1e-3 / 0.7 = 1.43e-3

re1 = 1 / 1.43e-3 = 700 Ohms

RB = [4200 * (700 + 100)] / [4200 + (700 + 100)] = 672 Ohms

rπ2 = 140 / 1.43e-3 = 97902 Ohms

g’m2 = 1.43e-3 * 97902 / (97902 + 672) = 1.42e-3

R’E = [4200 * (97902 + 672)] / [4200 + (97902 + 672)] = 4028.4 Ohms

ro2 = 75 / 1e-3 = 75000 Ohms

Ro = 1.42e-3 * 75000 * 4028.4 + 75000 + 4028.4 = 508053 Ohms

NPN simple current mirror with beta helper (1):

Given RE1 = RE2 = 100 Ohms

Io = 1 mA

Find RC:

1e-3 = (5 - 1.4) / (RC + 100) * 100/100

RC = 3500 Ohms

Find Vo,min:

Vo,min = 0.2 + 1e-3 * 100 = 0.3V

Find Ro:

gm1 = 1e-3 / 0.7 = 1.43e-3

re1 = 1/1.43e-3 = 700 Ohms

RB = [(3500/(140+1)+(140+1)*700/2)*((700+100)/140*(1+(140+1)^2*700/(2*3500)))*((140+1)*(700+100))]/ [(3500/(140+1)+(140+1)*700/2)+((700+100)/140*(1+(140+1)^2*700/(2*3500)))+((140+1)*(700+100))]

RB =

NPN simple current mirror with beta helper (2):

Given RE1 = 100 Ohms, RE2 = 50 Ohms

Io = 2 mA

Find RC:

2e-3 = (5 - 1.4) / (RC + 100) * 100 / 50

RC = 3500 Ohms

Find Vo,min:

Vo,min = 0.2 + 2e-3 * 50 = 0.3V

Find Ro:

gm1 = 1e-3 / 0.7 = 1.43e-3

re1 = 1/1.43e-3 = 700 Ohms

NMOS simple current mirror (1):

Given (W/L)1 = (W/L)2 = 17, Io = 100 uA

Find RC:

100e-6 = 70e-6 * 17 * (VGS1 – 1.4)^2

VGS1 = 1.11 or 1.69 V

100e-6 = (5 – 1.69) / RC

RC = 33100 Ohms

Find Vo,min:

Vo,min = 1.69 – 1.4 = 0.29V

Find Ro:

Ro = 1 / (100e-6 * 0.016) = 625000 Ohms

NMOS simple current mirror (2):

Given (W/L)1 = 17, (W/L)2 = 34, Io = 200 uA

Find RC:

100e-6 = 70e-6 * 17 * (VGS1 – 1.4)^2

VGS1 = 1.11 or 1.69 V

100e-6 = (5 – 1.69) / RC

RC = 33100 Ohms

Find Vo,min:

Vo,min = 1.69 – 1.4 = 0.29V

Find Ro:

Ro = 1 / (200e-6 * 0.016) = 312500 Ohms

PMOS simple current mirror:

Given (W/L)1 = (W/L)2 = 36, Io = 100e-6

Find RC:

100e-6 = 15e-6 * 36 (VSG1 – 1.65)^2

VSG1 = 1.22 or 2.08

100e-6 = (5 – 2.08) / RC

RC = 29200 Ohms

Find Vo,min:

Vo,min = 5 – (2.08 – 1.65) = 4.57 V

Find Ro:

Ro = 1 / (100e-6 * 0.01) = 1000000 Ohms

NMOS cascade current mirror:

Given W/L = 17, Io = 100 uA

Find RC:

100e-6 = 70e-6/2 * 17 * (VGS1 – 1.4)^2

VGS1 = 0.99 or 1.81 V

100e-6 = (2*5 – 2*1.81) / RC

RC = 63800 Ohms

Find Vo,min:

-5 + 1.81 + Vov1 = -5 + 2Vov1 + 1.4

Vov1 = 0.41 V

Vo,min = -5 + 1.81 + 0.41 = -2.78 V

Simulations:

Schematics:

NPN Simple Current Mirror:

NPN Simple Current Mirror with β Helper:

NMOS Simple Current Mirror:

PMOS Simple Current Mirror: 

NMOS Cascode Current Mirror:

DC sweep:

NPN simple circuit:

NPN simple current mirror with beta helper:

NMOS simple current mirror:

PMOS simple current mirror:

NMOS cascode current mirror:

Output Resistance:

NPN simple circuit:

NPN Simple Current Mirror with β Helper:

NMOS Simple Current Mirror:

PMOS Simple Current Mirror:

NMOS Cascode Current Mirror:

Measurements:

Io:

NPN Simple Current Mirror:

Io = 102 mV / 100 Ohms = 1.02 mA

NPN Simple Current Mirror with β Helper:

Io = 94 mV / 100 Ohms = 0.94 mA

NPN Simple Current Mirror with β Helper(2):

Io = 85 mV / 50 Ohms = 1.7 mA

NMOS Simple Current Mirror:

Io = 3.2 V / 33100 Ohms = 96.7 uA

PMOS Simple Current Mirror:

Io = 3.35 V / 29500 Ohms = 113.6 uA

NMOS Cascode Current Mirror:

Io = 6.255 V  / 63800 Ohms = 98.0 uA

Conclusion:

Calculations

Simulations

Measurements

Io(a)

1 mA

1 mA

1.02 mA

Io(b)

1 mA

1 mA

0.94 mA

Io(c)

2 mA

2 mA

1.7 mA

Io(d)

100 uA

100 uA

96.7 uA

Io(f)

100 uA

100 uA

113.6 uA

Io(g)

100 uA

100 uA

98.0 uA

Ro(a)

508k

350k

Ro(b)

350k

Ro(c)

625k

170k

Ro(d)

312k

350k

Ro(f)

1000k

750k

Ro(g)

70M

Vo(a)

0.3 V

0.3 V

0.25 V

Vo(b)

0.3 V

0.3 V

0.25 V

Vo(c)

0.3 V

0.3 V

0.25 V

Vo(d)

0.3 V

0.3 V

0.3 V

Vo(f)

4.57 V

4.45 V

4.55 V

Vo(g)

-2.78 V

-3 V

-3.1 V

In conclusion, the results from measurements matched with simulations and calculations, but I do have trouble in determine the method of measuring output resistance, since the introduction from lab introduction doesn’t work.

hihi

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