Part (A):
(V1-10)/1000+ (V1-V2)/1000+ V1/(5.1 x 1000)=0 (1)
(V2-V1)/1000+ V2/(3.3 x 1000)=0 (2)
V1= 6.99968 V
V2= 5.37185 V
Vth = V2 = 5.37185 V
Req1 = 1 kW // 5.1 kW
= 836.066 W
Req2 = Req1 + 1 kW
= 836.066 + 1000 = 1836.07 W
Req3 = Req2 // 3.3 kW
= = 1179.7 W
Req4 = Req3 + 1 kW
= 1179.7 + 1000 = 2179.7 W
Rth = Req4 = 2179.7 W
I 2kW =
= = 0.001285 A
I 2kW = 1.285 mA
Part (B):
Figure 1 below shows circuit (B) done by the PSPICE.
Figure 1: Circuit (B)
Part (C):
V-V1 N001 0 10V
R_R1 N002 N001 1k W
R_R2 N003 N002 1k W
R_R3 N004 N003 1k W
R_R4 0 N002 5.1k W
R_R5 0 N003 3.3k W
R_RL 0 N004 2k W
Part (D):
15 + 5.1 x 103*I1 + 2x103 (I1 – I2) =0 à (1)
-1x103*I2 – 2x103 (I2 – I1) – 5.1x103 (I2 – I3) = 0 à (2)
5.1x103 (I3 – I2) + 2x103*I3 – 1.5 = 0 à (3)
I1 = 0.002342 A
I2 = 0.000813 A
I3 = 0.000373 A
VL = I2 x 1 kW
VL = -0.000813 x 1000 = 0.813 V
Part (E):
Figure 2 below shows circuit (E)
Figure 2: Circuit (E)
Part (F):
Figure 3 below shows circuit (F)
Figure 3: Circuit (F)
Table 1 below shows the calculation for VL for part (D, E, F).
VL (voltage over the 1 kW resistor) |
Calculation Part D (No diode) |
PSPICE Part E (No diode) |
PSPICE Part F (with diode) |
1.V1 & V2 Present |
0.813 |
0.813 |
3.275 |
2.V1 only |
1.091 |
1.091 |
2.881 |
3.V2 only |
-0.278 |
-0.2782 |
7.151x10-6 |
4.Add line 2&3 |
0.813 |
0.8128 |
2.88099 |
5.% difference between line1 and line4 |
0% |
0.0246 % |
26.5347% |
Table 1: The Values of VL
For example:
% difference= x 100%= 0%
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