Securing Higher Grades Costing Your Pocket? Book Your Assignment at The Lowest Price Now!

# Sample Assignment Probability

41) (a) A Venn diagram b) P(RuF) = P(R)+P(F)-P(R-F)

=29/50+23/50-8/50

=44/50

=0.88

c) 14+18+6=38

P(only one sport)

=38/50

= 0.76

d) P(Volleyball/Rugby)

=P(VuR)/P(R)

=9/29

=0.31

e) P(Field Hockey/Not Rugby)=15/21

=5/7

=0.714

35) (a) P(A’) and P(B’)

=7/100x13/100

=91/10000

(b) P(A) and P(B)

=93/100x87/100

=8091/10000

(c) At least one of the test detects steroid = 1-None shows presence of steroid

= 1-91/10000

=9909/10000

6) a) We have to fill 4 spaces. We are left with 8 numbers to choose from (1,2,3,4,5,6,8,9)

4P4*7

7*5 ways – 5P48*7.

To eliminate zero, we fix zero in the first and rearrange the remaining number in the last four spaces. Hence, 4P4*7 such cases,

The total codes = 5P4*8*7)-4P4*7

=280-28

=252 codes

1. b) 3 as the third and 5 as the fifth=5!/(n-2)!

=5x4x3x2x1/(5-2)!

=120/6

=20 Codes

1. c) To begin with an even number, The 1st letter can be arranged in 4! Different forms starting with the four even numbers, that is 2,4,6,8

The 2nd,3rd, 4th and 5th can be arranged in 4! Ways. Hence, number of arrangement = 4!x4!

=576codes.

1. d) Begin and end with even number.

1st – 4!

5th – 4!

2nd, 4th and 5th can be arranged into 3! ways.

Hence, The total codes=4!x4!x3!

=576x6

23) Let 5 be the 1st digit. The other four digits can have either of the other 9 choices, as we have excluded 8. This gives 9^4 numbers.

Let 5 be the 2nd digit. The first digit can have either of 7 choices, excluding 5, 8 and 0. The other three digits can have any of the 9 choices. This gives 7 * 9^3 numbers.

Let 5 be the 3rd digit. The first digit can have either of 7 choices, excluding 5, 8 and 0. The 2nd digit can have 8 choices excluding 5 and 8. The other two digits can have any of the 9 choices. This gives 7 * 8 *9^2 numbers.

Let 5 be the 4th digit. The first digit can have either of 7 choices, excluding 5, 8 and 0. The 2nd and 3rd digits can have any of 8 choices. This gives 7 * 8^2*9 numbers.

Let 5 be the 5th digit. The first digit can have either of 7 choices, excluding 5, 8 and 0. The 2nd, 3rd and 4th digits can have any of 8 choices. This gives 7 * 8^3 numbers.

Hence, the total possible numbers;

= 9^4 + 7*9^3 + 7*8*9^2 + 7*8^2*9 + 7*8^3= 23816

## Submit Your Assignment Here #### AssignmentHippo Features

##### On Time Delivery

Our motto is deliver assignment on Time. Our Expert writers deliver quality assignments to the students.

##### Plagiarism Free Work

Get reliable and unique assignments by using our 100% plagiarism-free.

##### 24 X 7 Live Help

Get connected 24*7 with our Live Chat support executives to receive instant solutions for your assignment.

##### Services For All Subjects

Get Help with all the subjects like: Programming, Accounting, Finance, Engineering, Law and Marketing.

##### Best Price Guarantee

Get premium service at a pocket-friendly rate at AssignmentHippo

#### FREE RESOURCES

• Assignment Writing Guide
• Essay Writing Guide
• Dissertation Writing Guide
• Research Paper Writing Guide

#### FREE SAMPLE FILE

• Accounts
• Computer Science
• Economics
• Engineering

#### Client Review

I was struggling so hard to complete my marketing assignment on brand development when I decided to finally reach to the experts of this portal. They certainly deliver perfect consistency and the desired format. The content prepared by the experts of this platform was simply amazing. I definitely owe my grades to them.